Tolong bantu mr.crussader & Acim ^_^

1.
[tex]f^{1998}(11) \\ $Cek hasil dahulu$ \\ f^1(11)=(1+1)^2=2^2=4 \\ f^2(11)=4^2=16 \\ f^3(11)=(1+6)^2=7^2=49 \\ f^4(11)=(4+9)^2=13^2=169 \\ f^5(11)=(1+6+9)^2=16^2=256 \\ f^6(11)=(2+5+6)^2=13^2=169 \\ f^7(11)=(1+6+9)^2=16^2=256 \\ ... \\ $Untuk f orde genap, hasilnya 169$ \\ $Untuk f orde ganjil, hasilnya 256$ \\ $Maka,$ \\ f^{1998}(11)=169$ (Orde genap)$[/tex]

2.
[tex]f(x)=\sqrt{\frac{1}{2}x-8} \\ $Domainnya ketika f(x)\geq 0$ \\ \sqrt{\frac{1}{2}x-8}\geq 0 \\ \frac{1}{2}x-8\geq 0 \\ \frac{1}{2}x\geq 8 \\ x\geq 16 \\ D=\{x|x\geq 16,x\in R\}[/tex]