Bantuin kak,pakai cara perbandingan teorema pythagoras

mencari x
sin 30 
= [tex] \frac{opposite}{hypotenuse} = \frac{1}{2} \\ \frac{9}{hypotenuse} = \frac{1}{2}[/tex]
sisi miring = 2 x 9 = 18 cm

[tex] y^{2} = x^{2} - 9^{2} \\ y^{2} = 18^{2} - 81 \\ y^{2} = 324 - 81 \\ y^{2} = 243\\y = \sqrt{243} = 9 \sqrt{3} [/tex]