air bermassa 20kg bersuhu 20ºc dicampur dgn 10kg air bersuhu 80ºc.jika kalor jenis air 4200j/kgºc,hitunglah... A.kalor yg dlepas air 10kg B.kalor yg dterima air

Diketahui : m1 = 20 kg
C = 4200 j/kg
T1 = 20
m2 = 10 kg
T2 = 80
Ditanya :
A. Q lepas air2=
Jawab: Q lepas = Q terima
. . . . . . . m1c(Tc-T1) = m2c(T2-Tc)
. . . . . . . 20(Tc-20) = 10(80-Tc)
. . . . . . . 20Tc - 400 = 800 - 10Tc
. . . . . . . 30Tc = 1200
. . . . . . . Tc = 40
. . . . . . . M1c(Tc-T1)= 20.4200(40-20)
. . . . . . . . . . . . . . . . = 84000.20
. . . . . . . . . . . . . . . . = 1680000
gtw bener pada salah