Turunan fungsi f(x)=4x²+x⅔

Bab : Diferensial / Turunan

Pemyelesaian:
f(x) = 4x² + x^2/3
f'(x) = (2)4x²⁻¹ + (2/3)x^(2/3 - 1)
f'(x) = 8x + (2x/3)^(-1/3)
f'(x) = 8x + (3/2x)^1/3
f'(x) = 8x + ∛(3/2x)

Keterangan:
^ artinya pangkat