Tolong dijawab pakai cara,kisi2 ulangan mtk

-5-
a. tali busur
b. diameter
c. jari-jari
d. pusat lingkaran
e. busur

-6-
[tex]rumus \: sudut \: pusat = 2 \times sudut \: keliling \\ sudut \: pusat = 2 \times 85 = 170[/tex]

-7-
[tex]diameter = \frac{17}{2} = 8.5[/tex]

-8-
[tex]rumus \: luas \: juring = \frac{sudut}{360} \times luas \: lingkaran\\ luas \: juring = \frac{90}{360} \times \frac{22}{7} \times 21 \times 21 \\ luas \: juring = 346.5[/tex]

-9-
[tex] \frac{panjang \: busur}{2\pi \: r} = \frac{sudut \: pusat}{360} \\ \frac{pb}{2 \times \frac{22}{7} \times14 } = \frac{120}{360} \\ \frac{pb}{88} = \frac{1}{3} \\ 3pb = 88 \\ pb = 29.3[/tex]

-10-
[tex]d = \sqrt{ {p}^{2} - {(R - r)}^{2} } \\ d = \sqrt{ {20}^{2} - {(22 - 6)}^{2} } \\ d = \sqrt{400 - {16}^{2} } \\ d = \sqrt{400 - 256} \\ d = \sqrt{144} \\ d = 12[/tex]

Maaf kalo salah, semoga membantu
#maaf ya kemaren gk sempet