FISIKA HAMBATAN TOLONG DIJAWAB DIKUMPULIN BESOK pertanyaannya : kuat Arus ada penghambat 3ohm adalah? pake cara yaa

R1= 2 ohm
R2= 4 ohm
R3= 12 ohm
R4= 4 ohm
R5= 3 Ohm

V= 12 volt

Rseri1= R1+R2= 2+4= 6 ohm
1/Rpararel= 1/Rseri1 + 1/R3 + 1/R4
1/Rpararel= 1/6 + 1/12 + 1/4
1/Rpararel = 2/12 + 1/12 + 3/12
1/Rpararel= 6/12
Rpararel= 2 Ohm

Rseri2= Rpararel + R5
Rseri2= 2 + 3= 5 Ohm

I= V/R
I= 12/5
I= 2,4 Ampere