Matematika

Pertanyaan

Tugas
Dik: f(x) x^2 + 4x – 12
g(x) = x – 2

Tentukan

a. (f + g) (x)
b. (f - g) (x)
c. (f x g) (x)
d. (f/g)(x)

1 Jawaban


  • [tex]f(x) = {x}^{2} + 4x - 12 \\ g(x) = x - 2[/tex]
    nomor a
    [tex] {x}^{2} + 4x - 12 + x - 2 \\ {x}^{2} + 5x - 14 [/tex]
    nomor b
    [tex] {x}^{2} + 4x - 12 - (x - 2) \\ {x}^{2} + 4x - 12 - x + 2 \\ {x}^{2} + 3x - 10[/tex]
    nomor c
    [tex]( {x}^{2} + 4x - 12)(x - 2) \\ {x}^{3} - {2x}^{2} + {4x}^{2} - 8x - 12x + 24 \\ {x}^{3} + {2x}^{2} - 20x + 24[/tex]
    nomor d
    [tex] \frac{ {x}^{2} + 4x - 12 }{x - 2} = \frac{(x + 6)(x - 2)}{(x - 2)} = x + 6[/tex]


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