persamaan garis yang melalui titik 2,-4 dan 5,3 adalah

y-y1 / y2-y1 = x-x1 / x2-x1
y-(-4) / 3-(-4) = x-2 / 5-2
y+4 / 3+4 = x-2 / 3
y+4 / 7 = x-2 / 3
7(x-2) = 3(y+4)
7x-14 = 3y+12
7x-3y-14-12 = 0
7x-3y-26 = 0
atau
7x-3y = 26

[tex]x1 = 2 \\ x2 = 5 \\ \\ y1 = - 4 \\ y2 = 3 \\ \\ \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} \\ \frac{y - ( - 4)}{3 - ( - 4)} = \frac{x - 2}{5 - 2} \\ \frac{y + 4}{7} = \frac{x - 2}{3} \\ 7(x - 2) = 3(y + 4) \\ 7x - 14 = 3y + 12 \\ 7x - 26 = 3y \\ \frac{7x - 26}{3} = y[/tex]