nilai dari 2log 240 - 5 log 125 - 2 log 15 + 3 log27

Dit :
2log 240 - 5 log 125 - 2 log 15 + 3 log27

Penyelesaian :
Ingat bahwa
alog a = 1
alog a^b = b
alog b = 1/ blog a
alog b + alog c = alog (b · c)
alog b - alog c = alog (b / c)

2log 240 - 5log 125 - 2log 15 + 3log27
= 2log 240 - 2log 15 - 5log 125 + 3log 27
= 2log (240 / 15) - 5log 5^3 + 3log 3^3
= 2log 16 - 3 · 5log 5 + 3 · 3log 3
= 2log 2^4 - 3 · 1 + 3 · 1
= 4 · 2log 2 - 3 + 3
= 4 ·1 - 0
= 4

______________________
Referensi Logaritma : 
-> brainly.co.id/tugas/6398

Kelas 10 Matematika Bab 1 - Pangkat Akar dan Logaritma
Kata kunci : sifat logaritma
Kode soal : 10.2.1

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