jika invers fungsi f(x) adalah f^1(x)= 2x/3-x,maka f(-3)....

f(-3) = 2(-3) / 3+3
= -6/ 6
= -1

[tex]\displaystyle f(x)=\frac{2x}{3-x} \\ y=\frac{2x}{3-x} \\ 3y-xy=2x \\ 2x+xy=3y \\ x(2+y)=3y \\ x=\frac{3y}{y+2} \\ f^{-1}(x)=\frac{3x}{x+2} \\ \\ f^{-1}(-3)=\frac{3(-3)}{(-3)+2}=\frac{-9}{-1}=9[/tex]