tentukan nilai x dari [tex]( \sqrt{2} ) ^{x - 2} = \frac{1}{8 ^{x - 2} } [/tex]
Matematika
Farhan1802
Pertanyaan
tentukan nilai x dari
[tex]( \sqrt{2} ) ^{x - 2} = \frac{1}{8 ^{x - 2} } [/tex]
[tex]( \sqrt{2} ) ^{x - 2} = \frac{1}{8 ^{x - 2} } [/tex]
1 Jawaban
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1. Jawaban dharmawan14
(V2)^(x-2) = 1/8^(x-2)
(2^1/2)^(x-2) = (2^-3)^(x-2)
2^(1/2x-1) = 2^(-3x+6)
1/2x - 1 = -3x +6
1/2x + 3x = 6 +1
7/2x = 7
x = 2