Diketahui 2log 3=a dan 2log 5=b nilai 2log 360

2log 360 = 2log (36 x 2 x 5)
               = 2log 36 + 2log 2 + 2log 5
               = 2log (3² x 2²) + 1 + b
               = 2log 3² + 2log 2² + 1 + b
               = 2.2log 3 + 2.2log2 + 1 + b
               = 2a + 2(1) + 1 + b
               = 2a + b + 3
catatan
a log a = 1
a log a = alog (b x c)
a log (b x c) = alog b + alog c
a log b² = 2 a log b